Optimal. Leaf size=475 \[ \frac {\sqrt [3]{a+b x} (c+d x)^{2/3} \left (5 a^2 d^2 f^2-2 a b d f (9 d e-4 c f)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right )}{27 b^2 d^3}+\frac {(b c-a d) \log (a+b x) \left (5 a^2 d^2 f^2-2 a b d f (9 d e-4 c f)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right )}{162 b^{8/3} d^{10/3}}+\frac {(b c-a d) \left (5 a^2 d^2 f^2-2 a b d f (9 d e-4 c f)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right ) \log \left (\frac {\sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{d} \sqrt [3]{a+b x}}-1\right )}{54 b^{8/3} d^{10/3}}+\frac {(b c-a d) \left (5 a^2 d^2 f^2-2 a b d f (9 d e-4 c f)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right ) \tan ^{-1}\left (\frac {2 \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt {3} \sqrt [3]{d} \sqrt [3]{a+b x}}+\frac {1}{\sqrt {3}}\right )}{27 \sqrt {3} b^{8/3} d^{10/3}}+\frac {f (a+b x)^{4/3} (c+d x)^{2/3} (-5 a d f-7 b c f+12 b d e)}{18 b^2 d^2}+\frac {f (a+b x)^{4/3} (c+d x)^{2/3} (e+f x)}{3 b d} \]
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Rubi [A] time = 0.40, antiderivative size = 475, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {90, 80, 50, 59} \begin {gather*} \frac {\sqrt [3]{a+b x} (c+d x)^{2/3} \left (5 a^2 d^2 f^2-2 a b d f (9 d e-4 c f)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right )}{27 b^2 d^3}+\frac {(b c-a d) \log (a+b x) \left (5 a^2 d^2 f^2-2 a b d f (9 d e-4 c f)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right )}{162 b^{8/3} d^{10/3}}+\frac {(b c-a d) \left (5 a^2 d^2 f^2-2 a b d f (9 d e-4 c f)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right ) \log \left (\frac {\sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{d} \sqrt [3]{a+b x}}-1\right )}{54 b^{8/3} d^{10/3}}+\frac {(b c-a d) \left (5 a^2 d^2 f^2-2 a b d f (9 d e-4 c f)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right ) \tan ^{-1}\left (\frac {2 \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt {3} \sqrt [3]{d} \sqrt [3]{a+b x}}+\frac {1}{\sqrt {3}}\right )}{27 \sqrt {3} b^{8/3} d^{10/3}}+\frac {f (a+b x)^{4/3} (c+d x)^{2/3} (-5 a d f-7 b c f+12 b d e)}{18 b^2 d^2}+\frac {f (a+b x)^{4/3} (c+d x)^{2/3} (e+f x)}{3 b d} \end {gather*}
Antiderivative was successfully verified.
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Rule 50
Rule 59
Rule 80
Rule 90
Rubi steps
\begin {align*} \int \frac {\sqrt [3]{a+b x} (e+f x)^2}{\sqrt [3]{c+d x}} \, dx &=\frac {f (a+b x)^{4/3} (c+d x)^{2/3} (e+f x)}{3 b d}+\frac {\int \frac {\sqrt [3]{a+b x} \left (\frac {1}{3} \left (9 b d e^2-f (4 b c e+2 a d e+3 a c f)\right )+\frac {1}{3} f (12 b d e-7 b c f-5 a d f) x\right )}{\sqrt [3]{c+d x}} \, dx}{3 b d}\\ &=\frac {f (12 b d e-7 b c f-5 a d f) (a+b x)^{4/3} (c+d x)^{2/3}}{18 b^2 d^2}+\frac {f (a+b x)^{4/3} (c+d x)^{2/3} (e+f x)}{3 b d}+\frac {\left (\frac {5 a^2 d f^2}{b}-2 a f (9 d e-4 c f)+b \left (27 d e^2-36 c e f+\frac {14 c^2 f^2}{d}\right )\right ) \int \frac {\sqrt [3]{a+b x}}{\sqrt [3]{c+d x}} \, dx}{27 b d}\\ &=\frac {\left (\frac {5 a^2 d f^2}{b}-2 a f (9 d e-4 c f)+b \left (27 d e^2-36 c e f+\frac {14 c^2 f^2}{d}\right )\right ) \sqrt [3]{a+b x} (c+d x)^{2/3}}{27 b d^2}+\frac {f (12 b d e-7 b c f-5 a d f) (a+b x)^{4/3} (c+d x)^{2/3}}{18 b^2 d^2}+\frac {f (a+b x)^{4/3} (c+d x)^{2/3} (e+f x)}{3 b d}-\frac {\left ((b c-a d) \left (\frac {5 a^2 d f^2}{b}-2 a f (9 d e-4 c f)+b \left (27 d e^2-36 c e f+\frac {14 c^2 f^2}{d}\right )\right )\right ) \int \frac {1}{(a+b x)^{2/3} \sqrt [3]{c+d x}} \, dx}{81 b d^2}\\ &=\frac {\left (\frac {5 a^2 d f^2}{b}-2 a f (9 d e-4 c f)+b \left (27 d e^2-36 c e f+\frac {14 c^2 f^2}{d}\right )\right ) \sqrt [3]{a+b x} (c+d x)^{2/3}}{27 b d^2}+\frac {f (12 b d e-7 b c f-5 a d f) (a+b x)^{4/3} (c+d x)^{2/3}}{18 b^2 d^2}+\frac {f (a+b x)^{4/3} (c+d x)^{2/3} (e+f x)}{3 b d}+\frac {(b c-a d) \left (\frac {5 a^2 d f^2}{b}-2 a f (9 d e-4 c f)+b \left (27 d e^2-36 c e f+\frac {14 c^2 f^2}{d}\right )\right ) \tan ^{-1}\left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt {3} \sqrt [3]{d} \sqrt [3]{a+b x}}\right )}{27 \sqrt {3} b^{5/3} d^{7/3}}+\frac {(b c-a d) \left (\frac {5 a^2 d f^2}{b}-2 a f (9 d e-4 c f)+b \left (27 d e^2-36 c e f+\frac {14 c^2 f^2}{d}\right )\right ) \log (a+b x)}{162 b^{5/3} d^{7/3}}+\frac {(b c-a d) \left (\frac {5 a^2 d f^2}{b}-2 a f (9 d e-4 c f)+b \left (27 d e^2-36 c e f+\frac {14 c^2 f^2}{d}\right )\right ) \log \left (-1+\frac {\sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{d} \sqrt [3]{a+b x}}\right )}{54 b^{5/3} d^{7/3}}\\ \end {align*}
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Mathematica [C] time = 0.28, size = 175, normalized size = 0.37 \begin {gather*} \frac {(a+b x)^{4/3} \left (2 \sqrt [3]{\frac {b (c+d x)}{b c-a d}} \left (5 a^2 d^2 f^2+2 a b d f (4 c f-9 d e)+b^2 \left (14 c^2 f^2-36 c d e f+27 d^2 e^2\right )\right ) \, _2F_1\left (\frac {1}{3},\frac {4}{3};\frac {7}{3};\frac {d (a+b x)}{a d-b c}\right )-4 b f (c+d x) (5 a d f+7 b c f-12 b d e)+24 b^2 d f (c+d x) (e+f x)\right )}{72 b^3 d^2 \sqrt [3]{c+d x}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 11.95, size = 778, normalized size = 1.64 \begin {gather*} \frac {\sqrt [3]{d} \sqrt [3]{a+b x} \left (\frac {\sqrt [3]{a d+b (c+d x)-b c} \left (-5 a^2 d^2 f^2 (c+d x)^{2/3}+18 a b d^2 e f (c+d x)^{2/3}+3 a b d f^2 (c+d x)^{5/3}-8 a b c d f^2 (c+d x)^{2/3}+67 b^2 c^2 f^2 (c+d x)^{2/3}+54 b^2 d^2 e^2 (c+d x)^{2/3}+54 b^2 d e f (c+d x)^{5/3}-126 b^2 c d e f (c+d x)^{2/3}+18 b^2 f^2 (c+d x)^{8/3}-57 b^2 c f^2 (c+d x)^{5/3}\right )}{54 b^2 d^{10/3}}+\frac {\left (-5 a^3 d^3 f^2-3 a^2 b c d^2 f^2+18 a^2 b d^3 e f-6 a b^2 c^2 d f^2+18 a b^2 c d^2 e f-27 a b^2 d^3 e^2+14 b^3 c^3 f^2-36 b^3 c^2 d e f+27 b^3 c d^2 e^2\right ) \log \left (\sqrt [3]{a d+b (c+d x)-b c}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{81 b^{8/3} d^{10/3}}+\frac {\left (5 a^3 d^3 f^2+3 a^2 b c d^2 f^2-18 a^2 b d^3 e f+6 a b^2 c^2 d f^2-18 a b^2 c d^2 e f+27 a b^2 d^3 e^2-14 b^3 c^3 f^2+36 b^3 c^2 d e f-27 b^3 c d^2 e^2\right ) \log \left (\sqrt [3]{b} \sqrt [3]{c+d x} \sqrt [3]{a d+b (c+d x)-b c}+(a d+b (c+d x)-b c)^{2/3}+b^{2/3} (c+d x)^{2/3}\right )}{162 b^{8/3} d^{10/3}}+\frac {\left (-5 a^3 d^3 f^2-3 a^2 b c d^2 f^2+18 a^2 b d^3 e f-6 a b^2 c^2 d f^2+18 a b^2 c d^2 e f-27 a b^2 d^3 e^2+14 b^3 c^3 f^2-36 b^3 c^2 d e f+27 b^3 c d^2 e^2\right ) \tan ^{-1}\left (\frac {\sqrt {3} \sqrt [3]{b} \sqrt [3]{c+d x}}{2 \sqrt [3]{a d+b (c+d x)-b c}+\sqrt [3]{b} \sqrt [3]{c+d x}}\right )}{27 \sqrt {3} b^{8/3} d^{10/3}}\right )}{\sqrt [3]{a d+b d x}} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.65, size = 1400, normalized size = 2.95
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (b x + a\right )}^{\frac {1}{3}} {\left (f x + e\right )}^{2}}{{\left (d x + c\right )}^{\frac {1}{3}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.05, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (b x +a \right )^{\frac {1}{3}} \left (f x +e \right )^{2}}{\left (d x +c \right )^{\frac {1}{3}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (b x + a\right )}^{\frac {1}{3}} {\left (f x + e\right )}^{2}}{{\left (d x + c\right )}^{\frac {1}{3}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (e+f\,x\right )}^2\,{\left (a+b\,x\right )}^{1/3}}{{\left (c+d\,x\right )}^{1/3}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt [3]{a + b x} \left (e + f x\right )^{2}}{\sqrt [3]{c + d x}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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